A local university accepted 2,300 students out of 4,500 applicants for admission. What was the acceptance rate, expressed as a percent? (Show Work Please)

 2300/4500 = 23/45 = 0.511

As a percent,

   0.511*100% = 51.1%

Step-by-step explanation:

since 100% = 1, this is multiplying by 1

51.1%

Step-by-step explanation:

To find the answer you first need to find 1%=45

then you need to do 2300 divided by 45=51.1% or you can keep putting 111

Hope this is useful

i believe that the answer is

b. y-1=-2(x-4)

hope this !