A set of data with a mean of 53 and a standard deviation of 2.3 is normally distributed. Find the values that are 3 standard deviations from the mean.

A z-score is measured in units of the standard deviation. ... is two, the value 11 is three standard deviations above (or to the right of) the mean. ... The following two videos give a description of what it means to have a data set that is “normally” distributed. ... The z-scores for µ+3σ and µ–3σ are +3 and –3 respectively.

Step-by-step explanation:

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12

24

step-by-step explanation: