Gradient of line AB (3,7) and (5,11)​

Use the slope/gradient formula below:

This formula is for when we want to find the gradient when we have two given points. (We also call it Rise Over Run or changes of y over the changes of x.)

We are given two points which are (3,7) and (5,11). Substitute these points in the equation. (the ordered pairs are in (x,y) and not (y,x))

Hence, the gradient of AB is 2.

Answer

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form