On a coordinate plane, 4 lines are shown. Line A B goes through (negative 4, 3) and (4, 3). Line C D goes through (negative 3, 0) and (3, 2). Line F G goes through (negative 3, negative 1) and (3, negative 3). Line H J goes through (negative 1, negative 4) and (1, 2). Which of the lines that appear in the graph would be parallel to a line with a slope of 3 and a y-intercept at (0, 3)?

The line is HJ
Step-by-step explanation:
we know that
The formula to calculate the slope between two points is equal to

step 1
Find the slope line AB
we have
A(-4,-2),B(4,2)
substitute the values in the formula

step 2
Find the slope line CD
we have
C(-4,0),D(4,-4)
substitute the values in the formula

step 3
Find the slope line FG
we have
F(-3,-3),G(0,3)
substitute the values in the formula

step 4
Find the slope line HJ
we have
H(-1,3),J(1,-1)
substitute the values in the formula

step 5
Compare the slopes
we have

we know that
If two lines are perpendicular, then their slopes are opposite reciprocal
so
The slope of a line perpendicular to a line that has a slope of One-half must be negative 2
therefore
The line is HJ

Best answer that i found on yahoo ok   set :   x= length of 2nd piece in cm  x- 3= length of 1st piece in cm  x-4= length of 3rd piece in cm  then since you know they all came from the 20 cm ribbon you add them together and set them equal to 20x+ x-3 +x-4 = 20  3x - 7= 20  3x= 27  x= 9  the shortest piece is the third piece which is x- 4  x-4  9-4 = 5  the length of the smallest piece is 5 cm.  the other lengths are  9 cm  6 cm