Exhibit 11-3 The contents of a sample of 26 cans of apple juice showed a standard deviation of 0.06 ounce. We are interested in testing to determine whether the variance of the population is significantly more than .003. The null hypothesis . a. should not be rejected b. should be rejected c. should be revised d. None of these answers are correct.

a. should not be rejected

Step-by-step explanation:

H0 : σ² = 0.003

H1 : σ² > 0.003

We obtain the test statistic :

χ² = [(n - 1) * s²] ÷ σ²

s = sample standard deviation = 0.06

n = sample size = 26

σ² = 0.003

χ² = [(26 - 1) * 0.06²] ÷ 0.003

χ² = (25 * 0.06²) / 0.003

χ² = 30

Using the Pvalue from χ² calculator :

Pvalue = 0.2242

Using α = 0.05

Pvalue > α; we fail to reject the Null

d. millimeters per hour.

step-by-step explanation:

we are given that,

carlo used a rain gauge to measure the amount of water his lawn is receiving from the sprinklers.

since, according to the options, we see that,

water cannot be measured by 'miles per hour', 'meters per second' and 'grams per seconds'.

we get that, the water can be measured by 'millimeters per hour'.

hence, the appropriate rate for describing the amount of water is 'millimeters per hour'.