If the table shown below represents a function, then which is the possible value for f? A. –3
B. 0
C. 2
D. 3

C 2

Step-by-step explanation:

This is a parabolic function

Notice how we go negative and then positive

y = ax^2 +bx+c

Let x = 0

-5 = a(0) + b(0) +c

c = -5

y = ax^2 + bx -5

Let x = 3

4 = a(3)^2 +b(3) -5

Let x=-3

4 = a(3)^2 -b(3) -5

Add the two equations

4 = a(3)^2 +b(3) -5

4 = a(3)^2 -b(3) -5

8 = 2a (3)^2 - 10

18 = 2 a(9)

18 = 18a

a =1

Solving for b

4 = 1(3)^2 -b(3) -5

4 = 9 -3b -5

4 = 4 -3b

0 = -3b

0 =b

The equation is

y = (x)^2  -5

Letting y = -1

-1 =x^2 -5

Adding 5 to each side

4 = x^2

Taking the square root of each side

±2 = x

x= ±2

Given the choices

2: 10

step-by-step explanation:

let's first notice, the center of the hyperbola is at the origin, since the focus points are equidistantly 3 units away from the origin, that also means that the distance "c" from the center to either focus is 3.

it should also be notable that, the traverse axis for this hyperbola is vertical, or namely over the y-axis and therefore, the positive fraction will be the one with y-variable.

the traverse "a" component or distance from the center to either vertex is not 2, is more than 2, so we can safely put it at √5 ≈ 2.24.