Mathematics, 17.06.2021 09:50, kenndyllll

\begin{aligned} f(x)&=13-x h(x)&=x^2-6x-18 \end{aligned} f(x) h(x) =13−x =x 2 −6x−18 Write (f\circ h)(x)(f∘h)(x)left parenthesis, f, circle, h, right parenthesis, left parenthesis, x, right parenthesis as an expression in terms of xxx. (f\circ h)(x)=(f∘h)(x)=left parenthesis, f, circle, h, right parenthesis, left parenthesis, x, right parenthesis, equals

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\begin{aligned} f(x)&=13-x h(x)&=x^2-6x-18 \end{aligned} f(x) h(x) =13−x =x 2 −6x−18 Wri...