Three numbers have a mean of 12 and a mode of 9. What are the three numbers?

The three numbers are : 9, 9 and 18

Step-by-step explanation:

Since the mean is 12 the sum of the three numbers must be 36. This is because:

(let the three numbers be x y and z)

(x+y+z)/3=12

(x+y+z)=12*3

(x+y+z)=36

And since the mode is 9 two of the numbers must be 9.

So to find the third number;

9+9+z=36

z=36-18

z=18

81 seats

step-by-step explanation:

if you multiply 0.65 times 125 then you get 81.5 seats. well since you can't have half of a seat you have to round down and get 81 seats in the no children zones. that leave 44 seats outside of the no children zone.

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?