A bag contains exactly 50 coins. The coins are either worth 10 cents, 20 cents or 50 cents and there is Atleast one of each. The total value of the coins is $10. How many different ways can this occur?

This can happen in two ways:

1) 42 20-cent coins, 6 10-cent coins and 2 50-cent coins.

2) 30 10-cent coins, 10 20-cent coins and 10 50-cent coins.

Step-by-step explanation:

Given that a bag contains exactly 50 coins, and the coins are either worth 10 cents, 20 cents or 50 cents and there is at least one of each, and the total value of the coins is $ 10, to determine how many different ways can this occur, the following calculation must be performed:

48 x 0.5 + 1 x 0.2 + 1 x 0.1 = 24.30

48 x 0.1 + 1 x 0.2 + 1 x 0.5 = 5.5

48 x 0.2 + 1 x 0.1 + 1 x 0.5 = 10.3

45 x 0.2 + 4 x 0.1 + 1 x 0.5 = 9.9

44 x 0.2 + 5 x 0.1 + 1 x 0.5 = 9.8

42 x 0.2 + 6 x 0.1 + 2 x 0.5 = 10

30 x 0.1 + 10 x 0.2 + 10 x 0.5 = 10

Therefore, this can happen in two ways:

1) 42 20-cent coins, 6 10-cent coins and 2 50-cent coins.

2) 30 10-cent coins, 10 20-cent coins and 10 50-cent coins.

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v

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step-by-step explanation: