An envelope has an area of 40 square inches and a perimeter of 28 inches. What are the dimensions of the envelope?

10 inches by 4 inches

Step-by-step explanation:

Area of envelope, A = 40 in²

Perimeter of envelope, P = 28 in

Area = Length * width, L*W

Perimeter = 2(L + W)

40 = LW - - - (1)

28 = 2(L+W)

28/2 = L+W

14 = L+W - - - (2)

Solving like a quadratic equation ;

We need two numbers whose sum gives 14 and product gives 40

The numbers are 10 and 4

(10*4) = 40 and (10+4) = 14

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i

50*10 is greater

step-by-step explanation:

if you add the zero from 10 to 50, it will give you a bigger number.