Find one value of x that is a solution to the equation:
(x^2+4)^2 – 11(x^2+4) + 24 = 0

x = ±2

 x = ±i

Step-by-step explanation:

(x^2+4)^2 – 11(x^2+4) + 24 = 0

Let m = x^2 +4

(m)^2 – 11(m) + 24 = 0

Solving this quadratic

What two numbers multiply to 24 and add to -11

-8*-3 =24

-8-3 = -11

(m-8)(m-3) =0

m = 8   m=3

Now substitute back

x^2 +4 = 8    x^2 +4 = 3

x^2 +4-4 = 8-4    x^2+4-4 = 3-4

x^2 = 4                      x^2 = -1

Taking the square root

sqrt(x^2) = sqrt(4)                      sqrt(x^2) = sqrt(-1)

x = ±2                                           x = ±i

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation:

●yes, this statement is absolutely apt.

hope this you