Write a quadratic equation that has the solutions: 4 and -7

y = ( x-4)(x+7)

Step-by-step explanation:

When we know the zeros of the equation, we can write the equation in the form

y= a(x-z1) (x-z2)   where a is a constant and z1 and z2 are the zeros (solutions)

y = a( x-4)(x--7)

y =a( x-4)(x+7)

Since its says write an equation, we can pick a and I will let a=1

y = ( x-4)(x+7)

x = 25/2304

step-by-step explanation:

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.