Mary’s school is selling tickets to a choral performance. On the first day of ticket sales the school sold 4 senior citizen tickets and 2 child tickets for a total of $64. The school took in $204 on the second day by selling 12 senior citizen tickets and 8 child tickets. What is the price of one senior citizen ticket and one child ticket.

$13 - senior

$6 - child

Step-by-step explanation:

set up a system of equations:

s = senior tickets price

c = child tickets price

4s + 2c = 64; you can simplify this by dividing through by 2 to get:

2s + c = 32

12s + 8c = 204; you can simplify this by dividing through by 4 to get:

3s + 2c = 51

we can say that 'c' = 32-2s' and substitute that for 'c' in the second equation:

3s + 2(32-2s) = 51

3s + 64 - 4s = 51

-s = -13

s = 13

now find 'c' by substituting 13 for 's':

2(13) + c = 32

26 + c = 32

c = 6

theres no picture: /

step-by-step explanation:

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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