Line segments AB and CB intersect outside of circle P as shown below. What is the value of x?

4.5

Step-by-step explanation:

The Interesecting Secants Theorem states that when two secant lines intersect each other outside a circle, the products of their segments are equal. A secant is a straight line that cuts a curve in two or more points, so this definitely applies here, as both AB and CB interesect the circle twice.

Using this theorem, we can say that 6*3=4*x, so 18=4*x and x=4.5

i cant see the graph

step-by-step explanation:

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)