The area of a wall that needs to be papered is 84sqft. The wallpaper that needs to be papered is 18in wide and 33ft long. Rolls of solid color wallpaper will be used, so patterns do not have to match up.

The answer is below

Step-by-step explanation:

The area of the wall is 84 ft².

The width of the wallpaper is 18 in.

1 ft. = 12 in

Hence; 18 in = 18 in * 1 ft. per 12 in = 1.5 ft

The length of the wallpaper is 33 ft.

Therefore, the area of the wallpaper = length * width = 1.5 ft. * 33 ft. = 49.5 ft². This means that each roll of wallpaper has an area of 49.5 ft²

Therefore, the minimum amount of rolls of wallpaper needed = area of wall / area of wallpaper

Amount of wallpaper = 84 ft² / 49.5 ft² = 1.7 rolls

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step-by-step explanation:

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)