Mathematics, 14.06.2021 06:20, kevinh2683
Part of a cross-country skier's path can be described with the vector function r = <2 + 6t + 2 cos(t), (15 β t)(1 β sin(t))> for 0 β€ t β€ 15 minutes, with x and y measured in meters.
The derivatives of these functions are given by xβ²(t) = 6 β 2sin(t) and yβ²(t) = β15cos(t) + tcos(t) β 1 + sin(t).
1. Find the slope of the path at time t = 4. Show the computations that lead to your answer.
2. Find the time when the skier's horizontal position is x = 60.
3. Find the acceleration vector of the skier when the skier's horizontal position is x = 60.
4. Find the speed of the skier when he is at his maximum height and find his speed in meters/min.
5. Find the total distance in meters that the skier travels from t = 0 to t = 15 minutes.
Answers: 2
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Part of a cross-country skier's path can be described with the vector function r = <2 + 6t + 2 co...
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