Is calculated for households water. Here is some information about
here are several charges on a municipal account that vary according to the peo
stoperty you own and how much water you consume. The details are as follows
Single-residential properties
Property rates are based on the total value of the property (building and land) The
tate is 0,989c for every rand of the property value (per year).
Refuse collection charge is R38,60 for a wheelie bin (monthly charge)
Water consumption is charge on a stepped tariff. The more water you use, the more
expensive it becomes. The table below shows the monthly charges:
Water consumption (1) Charge per kilolitre (R)
free
0-6
2,73
7-20
21-40
4,30
5,46
41-60
The first 6 kl of water are free
The next 14 kl cost R2.73 for each kilolitre.
The next 20 kl cost R4,30 for each kilolitre.
The next 40 kl cost R5,46 for each kilolitre,
1.1
What will the annual Property rates be for one year for a property that is worth (2)
R250 000? Give your answer in Rand.
(2)
1.2
How many kilolitres of water are free per household every month?
1.3
For how many litres of water will a household actually pay if 25 kilolitres were (2)
used in the month?
For how many kilolitres of your answer in 1.3 will you pay at a tariff of R4, 30 per (2)
Calculate the cost for using 9,5 kl in one month and then add VAT of 15% to the (5)​

step-by-step explanation:

30% of $420 is 0.30($420) = $126 and $420 + $126 = $546.

or, 130% of $420 is 1.3($420) = $546.

notice that this is not the $600 original list price with which we started.

why doesn't this work?

the method does not work because 30% of $420 is not the same amount as the 30% of $600. it may seem obvious when stated this way, but it is a very common error made on problems of this type. we cannot just use the same percent and get back to the original amount because we are taking that percent of a different value.

to work problems of this type correctly, it is generally best to write an equation for the situation and then solve.

example: since (100% – 30%)(original price) = (sale price)

70% of the   (original price) is $420.

0.7x   = 420

equation image indicator

x = 600

the original cost was $600.

we may also solve this problem using the two-step method. working the problem in two steps requires us to use more algebra skills. we have to know that x = 1x (identity property of multiplicationtext annotation indicator) and that 1x – 0.3x = 0.7x (subtracting like terms). then we solve the problem as follows:

(original price) – 30%(original price) = sale price

x – 0.3x = 420

0.7x = $420

equation image indicator

x = 600

the original cost was $600.  

note that with both of the above methods we do obtain the correct original amount.

example: after a 5% pay raise, hermione is earning $22,680 per year. what was she earning before the pay raise?

105% of (original salary) = current salary

1.05x = 22,680

equation image indicator

x = 21,600

hermione earned $21,600 per year before the pay raise.

this is an example so maybe you will get how to at least do it!

you have orange juice on wednesday. (idk why this is the answer)

step-by-step explanation:

i think the answer is c sorry if it's wrong