Find a diginacci sequence with no equal term to 11: quick answer please

uhh hope this helps

Step-by-step explanation:

A Diginacci sequence is created as follows.

• The first two terms are any positive whole numbers.

• Each of the remaining terms is the sum of the digits of the previous

two terms.

For example, starting with 5 and 8 the Diginacci sequence is

5, 8, 13, 12, 7, 10,. . .

The calculations for this example are

5 + 8 = 13, 8 + 1 + 3 = 12, 1+ 3 +1+ 2 = 7, 1 + 2 + 7 = 10.

a) List the first 26 terms of the Diginacci sequence above.

b) Find, with explanation, two starting terms for a Diginacci sequence

so that its 2021st term is 11.

c) Find, with explanation, a Diginacci sequence that has no term equal

to 11.

d) Find, with explanation, a sequence with two different starting terms

which contains five consecutive terms that are even and not all identical

Both 2 and 3 is correct.

c

step-by-step explanation:

at least i think its

the direct variation says that:

then the equation is of the form is given by:

            where k is the constant variation.

from the given table:

consider any value of x and m(x)=y

x = 2 and m(x)=y = 3

substitute these value in [1]; we have;

divide both sides by 2 we get;

⇒

check:

put x = -1 and m(x) = -1.5

substitute in the equation:

-1.5 = -1.5                   true

therefore, the function m(x) represents a direct variation

graph of this function as shown below: