NO LINKS OR ELSE YOU'LL BE REPORTED! Only answer if you're very good at math. No guessing please. A student is standing 20 feet away from the base of a tree. He looks to the top of the tree at a 50° angle of elevation. His eyes are 5 feet above the ground. Using cos 50=0.64,what is the height of the tree to the nearest foot?

A: 24 feet

B: 36 feet

C: 29 feet

D: 31 feet​

29 feet

Step-by-step explanation:

Solving this question above, we using Trigonometric function tangent = Opposite/Adjacent

Opposite side + h = Height of the tree

We are told that:

A student is standing 20 feet away from the base of a tree. He looks to the top of the tree at a 50 degree angle of elevation. His eyes are 5 feet above the ground.

20 feet = Adjacent side = Distance form the tree

tan 50 = (h+5)/20

Cross Multiply

h + 5 = 20 × tan50

h = 20tan50 - 5

h= 23.835071852

h =23.84

Therefore the height of the tree is calculated as:

23.84+5 feet

=28.84 feet

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b