From her eye, which stands 1,61 meters above the ground, Savannah measures the angle of elevation to the top of a prominent skyscraper to be 24°. If she is standing at
a horizontal distance of 340 meters from the base of the skyscraper, what is the
height of the skyscraper? Round your answer to the nearest hundredth of a meter if
necessary

152.99 m

Step-by-step explanation:

Using the solution diagram attached below :

We can obtain the height, h of skyscraper to the position of her eye level using trigonometry ;

Tan θ = opposite / Adjacent

Tan 24 = h / 340

h = tan 24 * 340

h = 151.37775

Hence, the height will be (h + distance from eyelevel to ground)

151.37775 + 1.61

= 152.98775

= 152.99 m

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.