A baseball is thrown straight up in the air with an initial velocity of 128 feet per second from a point
exactly 4 feet off the ground.
Write the function for the height of this object at any
time (t seconds)

Step-by-step explanation:

where

h(t) is the height of the ball after a certain amount of time has gone by,

-16t² is the pull of gravity in ft/s/s,

v₀t is the initial upwards velocity, and

h₀ is the height from which the ball was initially thrown. Our equation is then, filling in the info in the correct places:

where 128 is the given initial velocity and 4 is the number of feet from which the ball was initially launched.

1/6

step-by-step explanation:

-8/2y-8=5/y+4-7y+8/y^2-16

we move all terms to the left:

-8/2y-8-(5/y+4-7y+8/y^2-16)=0

we can not solve this equation