Some fireworks are fired vertically into the air from the ground at an initial velocity of 96 feet per
second. Find the highest point reached by the
firework - just as it explodes.
A. 144 ft
B. 32 ft
C. 100 ft
D. 96 ft

yo

step-by-step explanation:

yo

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

96 39 cause 135 -96=39 im smart (i used a calculater)