Can someone solve with steps (EASY)

please tell which class then I can helpGiven equation line,

3x−4y+2=0

∴4y=3x+2

y=(

4

3

)x+

2

1

Slope of given line=

4

3

As slope of parallel lines are equal

∴ Slope of line parallel to given line =

4

3

Equations of line passes through (−2,3) with slope (

4

3

) is

(y−3)=

4

3

(x+2)

4y−12=3x+6

3x−4y+18=0 be the equation of line parallel to 3x−4y+2=0 and passing through (−2,3)

yo answer should be 6 if im not mistaken

step-by-step explanation:

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.