Solve x^2-16x + 89 = 0 using the Quadratic Formula.

In solving a quadratic equation of the form ax² + bx + c = 0 by completing the square , we obtain two roots of x. Those roots can be written as where a is the coefficient of x² , b is the coefficient of x and c is the constant term. We use this formula to find the required solutions of the given quadratic equation.

Here , a = 1 , b = -16 and c = 89

The square root of negative number does not exist in the set of real numbers. So, This cannot be further solved!

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Problem:Solve it using quadratic formula.

The standard form of:

Given that:a = 1b = - 16c = 89This has a discriminant ∆ given by the formula:

Since ∆ < 0 this equation has no real solutions, only complex ones.One way of finding the solutions is using the quadratic formula:

So the final answer is:

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Is this from a

This makes absolutely no sense at all young man/women