Use the image below to answer the following question. Find the value of sin x^0 and cos y^0. What relationship do the ratios of sin x^0 and cos y^0 share?

sin x = 3/5

cos y  = 3/5

sin x and cos y are equal

Step-by-step explanation:

First we need to find the length of the hypotenuse

We can use the Pythagorean  theorem

a^2+ b^2 = c^2  where a and b are the legs and c is the hypotenuse

6^2 +8^2 = c^2

36+64 = c^2

100 = c^2

Taking the square root

sqrt(100) = sqrt(c^2)

10 = c

The hypotenuse is 10

Since this is a right triangle we can use trig functions

sin x = opp side/ hypotenuse

sin x = 6/10 = 3/5

cos y = adj / hypotenuse

cos y = 6/10  = 3/5

sin x and cos y are equal

Sin x ° = 3/5

Cos y ° = 3/5

Sin x and Cos y both are equal.

Step-by-step explanation:

Firstly we need to Find the hypotenuse

Using Pythagoras theorem

(Perpendicular)² + (Base)² = (hypotenuse)²

substitute the values

( 8 )² + ( 6 ) ² = ( hypotenuse )²

Evaluate the exponent

64 + 36 = ( hypotenuse ) ²

Adding 36 and 64

100 = ( hypotenuse ) ²

Taking square root of 100.

√100 = hypotenuse

10 = hypotenuse

Since, It is right triangle we can use trigonometry functions

Sin x = opposite side/hypotenuse= 6/10

Sin x° = 3/5

Cos y = adjacent side/hypotenuse = 6/10 Cos y° = 3/5

Sin x ° and Cos y° are equal.

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