The birth weights (in kilograms) of 5 elephants, selected randomly, are 133, 120, 97, 106, 124 (Source: www. elephant. se). Below are the summary statistics of the data and output from the analysis testing if the true average birth weight of the elephants is 100 kg. min Q1 median Q3 max mean sd n missing
97 106 120 124 133 116 14.40 486 5 0
t = 2.4837, df = 4, p-value = 0.06794
alternative hypothesis: true mean is not equal to 100 95 percent confidence interval:

What is the correct calculation of a 95% confidence interval for the true average birth weight of elephant?
(i) 116± 1.96 x 14.4
(ii) 116 ± 1.96 x 14.4/15
(iii)116 ±1.96 x 14.4/14
(iv) 116 ± 2.4837 x 14.4
(v) 116 ±2.4837 x 14.4/15
(vi) 116 ± 2.4837 14.4/74
(vii) 116 ± 2.78 x 14.4
(viii) 116 ± 2.78 x 14.4√5
(ix) 116 ±2.78 x 14.4√4

(viii) 116 ± 2.78 x 14.4√5

Step-by-step explanation:

The given data is

Sample size =n= 5

Calculated t- value= 2.4837

Mean= 116

Standard deviation= sd= 14.40486

The t - value from table with 4 d.f for ∝/2 is  t∝/2 (n-1)= 2.776

The 95% confidence interval is calculated by

d` ± t∝/2 (n-1)  *sd/√n

Putting the values

116 ± 2.776* 14.40486/√5

Comparing these values with the options Part viii gives the best answer.

(viii) 116 ± 2.78 x 14.4√5

2.776 when rounded gives 2.78 and 14.40486 when  rounded gives 14.4

The rest are incorrect.

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

ok then what happened.