Mathematics, 09.06.2021 23:50, lmgarrabrant8587

Solve for p $-\frac{1}{3} (2-6p)=-\frac{8}{3} +p$

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$a: p=-\frac{6}{7} \\\\b: p=-2\\\\c: p= \frac{5}{6} \\\\\ d: p=\frac{2}{3}$

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Solve for p $-\frac{1}{3} (2-6p)=-\frac{8}{3} +p$

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