Suppose that 6% of people are left handed and suppose you pick two people at random. Rounding your answer to two decimal places, find the probability that

The probability that neither person is left-handed is 88.36%, that only one is left-handed is 5.64%, and that both are left-handed is 0.36%.

Step-by-step explanation:

Supposing that 6% of people are left handed and supposing two people are picked at random, to find the probability that 0, 1 or 2 people are left-handed, the following calculation must be performed:

100 - 6 = 94

0 left-handed people = 0.94 x 0.94 = 0.8836 = 88.36%

1 left-handed person = 0.94 x 0.06 = 0.0564 = 5.64%

2 left-handed people = 0.06 x 0.06 = 0.0036 = 0.36%

Therefore, the probability that neither person is left-handed is 88.36%, that only one is left-handed is 5.64%, and that both are left-handed is 0.36%.

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b: |12 – x| ≤ 0.25

step-by-step explanation:      

let x be the possible lengths in inches, of the ribbons jaime cut.

we have been given that jaime is cutting strips of ribbon for a project. he tries to cut each piece to be 12 inches long, but sometimes he cuts it too long or too short by as much as 0.25 inch.  

we can represent this information in an inequality as:

by the definition of absolute value function we will get,

upon combining our inequalities we will get,

therefore, the inequality   describes all the possible lengths (x), in inches, of the ribbons jaime cut.

step-by-step explanation: