Find a​ point-slope form for the line with slope 1/5 and passing through the point ​(-6,-4)

(y +4) = 1/5( x +6)

Step-by-step explanation:

Point slope form is

(y-y1) = m(x-x1) where m is the slope and (x1,y1) is a point on the line

(y - -4) = 1/5( x - -6)

(y +4) = 1/5( x +6)

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204