Tn=2n-5 write down four term in a sequence

- 3, - 1, 1, 3

Step-by-step explanation:

To find the first four terms, substitute n = 1, 2, 3, 4 into the rule

T₁ = 2(1) - 5 = 2 - 5 = - 3

T₂ = 2(2) - 5 = 4 - 5 = - 1

T₃ = 2(3) - 5 = 6 - 5 = 1

T₄ = 2(4) - 5 = 8 - 5 = 3

The first 4 terms are - 3, - 1, 1, 3

Four terms will be :7,9,11,13

Step-by-step explanation:

Given :

Tn=2n-5

Now, putting the value of n=1,2,3,4

T(1)=2(1)+5

T(1)=7

T(2)=2(2)+5

T(2)=9

T(3)=2(3)+5

T(3)=11

T(4)=2(4)+5

T(4)=13

answer: a) (0,0), (1,1), (2,8), and (3,27).

step-by-step explanation:

0^3=0

1^3=1

2^3=8

3^3=27

in effect, the exponential equation for this would me y=3^x. each x-coordinate cubed is giving the y coordinate, so a is your answer : )

f(2x−x2)=−3x2+6x−1

step-by-step explanation:

set up the composite function and evaluate.

f(2x−x2)=−3x2+6x−1