If we have eight decisions to make and 3 choices for each decision, how can we represent the number of potential outcomes?

For the first question the answer is a, for the second c, for the third d, for the 4th b, for the 5th a

The question is kind of confusing. if it's asking how many variations of answers can you give. then do 4^5 for your answer.this would be something like the first question could be a and the 2nd c or first b next c etc. if you can, ask the teacher for a better confirmation of what it's asking. if i'm assuming correctly what it's asking, it's 625 different variations.