Use the function h(t) = -167 + C, where t is the number of seconds and c is the
height of the bridge. How high above the
ground is a ball that was dropped off a
260-foot-high bridge after 2 seconds?
A O feet
B 64 feet
C 196 feet

Ball distance from ground = 74 feet

Step-by-step explanation:

Given function;'

h(t) = -167(t) + C

t = number of seconds

c = height of the bridge

Find:

Ball distance from ground

If,

c =  260-foot-high bridge

t = 2 seconds

Computation:

h(t) = -167(t) + C

h(2) = -167(2) + 260

h(2) = -334 + 260

h(2) = -74

Ball distance from ground = 74 feet

answer: 140

step-by-step explanation:

so just add all then it will be your answer but i am not pretty sur eif it is but hope this i am here to people