I NEED HELP WITH THIS PLEASE ITS DUE TONIGHT

Work Shown:

(tangent)^2 = (whole secant)*(external secant)

(TU)^2 = (RT)*(ST)

(TU)^2 = (RS+ST)*(ST)

(TU)^2 = (8+4)*(4)

(TU)^2 = 48

TU = sqrt(48)

TU = 6.928203

TU = 6.9

For more info, you can search out "secant tangent chord", or something similar, and you should get to a page that describes the formula of what's going on here. This should match up fairly similarly to what lesson 3.09 is talking about.

9.8

TU^2= TS x TR

TU^2= 8 x 12

TU= sqrt(96) = 9.79

9 sandwiches per hour

step-by-step explanation:

when we have a rate, we want a 1 in the denominator

27/3 = 9

27 sandwiches/ 3 hours = 9 sandwiches/hour

the answer is:

the correct option:

b.

to solve the problem, we need to remember how to operate to simplify exponential expressions using the logarithms.

we are given the equation:

then, using placing logarith with base 7 on both sides of the equation, we have:

so, rounding the obtained result to two decimal places (nearest hundreth), we have:

hence, we have that the correct option:

b.

have a nice day!