If a value started at 1000, Increased 7 times, and ended at 12000, how much did the value increase each time?

the value of increase each time is 1,571.43

Step-by-step explanation:

Given;

original value of the number, A = 1000

final value of the number, N = 12,000

Assuming the number increased equally each time, let the value of increase each time = x

The following linear equation will be obtained to solve for x;

7x + 1000 = 12,000

7x = 12,000 - 1,000

7x = 11,000

x = 11,000/7

x = 1,571.43

Therefore, the value of increase each time is 1,571.43

  b.   the average rate of change of f(x) is less than the average rate of change of g(x).

step-by-step explanation:

since the length of the interval is the same in each case, we only need to compare the change in y-value to see which is greater.

so the change in y-value for function f is (6 )) = 9.

the table tells us

so the change in y-value for function g is (31 -1) = 30.

the change in y-value of f(x) on the interval is less than the change in y-value of g(x) on the same interval, so the average rate of change of f(x) is less than the average rate of change of g(x).

answer: 298143

step-by-step explanation: