ABC is a right angled triangle AC=6cm
AB=20cm
Calculate length of BC
Give answer to 1 decimal place

19.1cm

Step-by-step explanation:

AB=20

AC=6

BC=?

So,by Pythagoras Theorem:-

AC2=AB2+BC2

Therefore:-

AB2-AC2=BC2

400-36=BC2

√364=BC2

19.1=BC2

19.1 cm

I don't have a picture so I hope this is what you mean/

Step-by-step explanation:

AB²-AC²=BC²

20²-6²=BC²

400-36=BC²

364=BC²

√364=√BC²

BC≈19.1

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180