Find measure of angles B, E, D and C and the length of BC. Triangle ABC ~ Triangle DEF. Measure of angle A = 30 degrees and measure of angle F = 65 degrees. AB=20, DE = 35, EF= 28.

< B = 180-30-65=85°

< E = 85°

< D = 30°

< C = 65°

BC = 20/35 × 28 = 16

<D = 30

< C = 65

<B = <E = 85

16 = BC

Step-by-step explanation:

ABC ~ Triangle DEF

<A = <D = 30

< C = <F = 65

Since they are similar triangles

A+ C + B = 180 since the angles of a triangle = 180

30+65+B =180

95+ B = 180

<B = 180 -95 = 85

<B = <E = 85

The triangles are similar so the sides are proportional

AB      BC

 =

DE      EF

20      BC

 =

35      28

Using cross products

20*28 = 35 BC

Divide each side by 35

20*28/35 = 35/35 BC

16 = BC

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."

his first public project he is asked to create a small scale drawing. the garden is a right triangle with base 25m and height 30m. are you trying to solve for the last side/hypotenuse? the irrational form of the answer would be 5\sqrt{61}