In 2009, a school population was 1,700. By 2017 the population had grown to 2,500. Assume the population is changing linearly. Find an equation for the population, P, of the school t years after 2009.

P(t) = 100t + 1900

Step-by-step explanation:

∆P = 2500 - 1700 = 800

∆t = 2017 - 2009 = 8

m = ∆p/∆t = 800/8 = 100

b = initial pop = 1900

using slope intercept form

P(t) = 100t + 1900

nlgqer

step-by-step

p ÷ r = tan(x)

step-by-step explanation:

given that there is a figure below shows a right triangle: a right triangle is shown with hypotenuse equal to q units and the length of the legs equal to p units and r units.

graph is missing so i will create the graph as per given information.

the angle between the legs having lengths p units and q units is y degrees. the angle between the legs having lengths r units and q units is x degrees.

now we need to find about what is p ÷ r equal to.

so we can use trigonometric ratio tan(x)=[altitude]/[base] to find the value of p ÷ r, because p is the altitude and r is the base.

p ÷ r=tan(x)

hence final answer is p ÷ r=tan(x).