In the accompanying diagram of circle O, chords AB and CD intersect at E. If AE = 3, EB = 4, CE = x, and ED = x + 1, find. CE.

CE = 3

Step-by-step explanation:

Given:

AE = 3

EB = 4

CE = x

ED = x + 1

Required:

CE

Solution:

First we need to determine the value of x by generating am equation as follows:

CE × ED = AE × EB (Interacting Chords Theorem)

Substitute

x × (x + 1) = 3 × 4

x² + x = 12

Subtract 12 from each side

x² + x - 12 = 12 - 12

x² + x - 12 = 0

Factorize to find the value of x

x² + 4x - 3x - 12 = 0

x(x + 4) -3(x + 4) = 0

(x - 3)(x + 4) = 0

x - 3 = 0

x = 3

Or

x + 4 = 0

x = -4

Let's use the positive value of x

CE = x = 3

-3.396 = -3.4

-0.708 = -0.7

0.304 = 0.3

0.955 = 1

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b