Can someone please help for this question?

Write the conditions in algebra.
x = y + 2
3x + 4y = 8x - 20
From the first equation y = x - 2. Substitute for y in the second equation.
3x + 4(x - 2) = 8x - 20
3x + 4x - 8 = 8x - 20
7x = 8x - 12
So x = 12

You should always check your answers for simultaneous equations
y = 10 because x = y + 2
3 x 12 + 4 x 10 = 8 x 12 - 20?
36 + 40 = 96 - 20. This is true!

For a multi choice problem it would be faster to just try each value until one works