Consider the relation y → 4 x−1 for the domain {3, 5, 7, 9} (a) Calculate the values for the range.

{ 11, 19, 27, 35 }

Step-by-step explanation:

To find the range substitute each value of x from the domain into the relation

x = 3 : y → 4(3) - 1 = 12 - 1 = 11

x = 5 : y → 4(5) - 1 = 20 - 1 = 19

x = 7 : y → 4(7) - 1 = 28 - 1 = 27

x = 9 : y → 4(9) - 1 = 36 - 1 = 35

range is { 11, 19, 27, 35 }

y=3n + 1

step-by-step explanation:

this is wrong because it says the second number is one less and i added one instead