Quadrilateral QRST is inscribed in the circle. Find the measurements of each of the angles in Quadrilateral QRST. Show your work. (x-6) (x+12) (x-4) ​

Given- O is the centre of a circle in which an equilateral ΔPQR has been inscribed.

To find out- ∠QOR=?

Solution- The points P, Q & R are on the circumference of the circle since ΔPQR has been inscribed in the circle. Now the chord QR subtends ∠QOR to the centre O and ∠QPR to the circumference at P.

∴ By rule, ∠QOR=2∠QPR(i).

Now PQR is an equilateral Δ. Each of its angle is 60

o

. i.e ∠QPR=60

o

.

So, from (i), ∠QOR=2∠QPR=2×60

o

=120

o

.

Ans- Option B.

solution

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