What are the x-intercepts of the equation y=4x^2-16

x = ± 2

Step-by-step explanation:

To find the x- intercepts let y = 0 , that is

4x² - 16 = 0 (add 16 to both sides )

4x² = 16 ( divide both sides by 4 )

x² = 4 ( take the square root of both sides )

x = ± = ± 2

The x- intercepts are x = - 2 and x = 2

I love algebra anyways  

the ans is in the picture with the steps  

(hope it helps can i plz have brainlist :D hehe)

Step-by-step explanation:

do i do it on a graph?

step-by-step explanation: