Factorise fully 2a^2b + 6ab^2​

2ab(a + 3b)

Step-by-step explanation:

2a²b + 6ab²​

Factor out 2ab

2ab(a + 3b)

Step-by-step explanation:

2a^2b + 6ab^2

take common

2 can be taken common because there is 2in first term and there is 6 in second term and 2 can exactly divide 6 .there is a*a in first term and only a in second term so u can take a as common.There is only b in first term and b*b in second term so take u can take b as common.

total we can take

2ab as common.So,

2ab(a+3b)

therefore 2ab(a+3b) is the required answer.

y = 5x + 17

step-by-step explanation:

a perpendicular line will be the opposite reciprocal slope of the given equation.   the slope given is -1/5 so the opposite reciprocal is 5

find b:

7 = 5 (-2) + b

7 = -10 + b

17 = b

write equation

y = 5x + 17

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)