Given that cot(θ)= -√5/3 and cos(θ) < 0, find sin(θ)

D. 3√14 /14

Step-by-step explanation:

given that cot(θ)= -√5/3 and cos(θ) < 0

cot(θ)= -√5/3 and cos(θ) < 0, the angle should be on quadrant II.

cot(θ)= -√5/3 => x = -√5 , y = 3

h = √(-3)²+5 =√14

so, sin(θ) = y/h = 3/√14 = 3√14 /14

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )