The manager of a football team says the probability that the team will win the next match is 0.6 and the probability it will lose is is 0.1 Find the probability that the team will: a) not win b) not lose c) not draw

A. 0.4

B.0.9

C.0.7

Step-by-step explanation:

Answers:

Explanation:

Part (a)

P(winning) = 0.6 is given

The probability of not winning is 1 - P(winning) = 1 - 0.6 = 0.4

Part (b)

P(losing) = 0.1 is given

The probability of not losing is 1 - P(losing) = 1 - 0.1 = 0.9

Part (c)

The probability of winning is 0.6 and the probability of losing is 0.1

This adds to 0.6+0.1 = 0.7, which must mean 0.3 is the probability of drawing (since 0.7+0.3 = 1)

So the probability of not drawing is 1 - P(draw) = 1 - 0.3 = 0.7, which is exactly the sum of the probabilities of winning and losing.

step-by-step explanation:

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