Mathematics, 05.06.2021 22:40, msanger7587

An object was shot up into the air with an initial vertical speed of 544 feet per second. Its height as time passes can be modeled by the quadratic equation y = -16t^2+ 544+. Here t represents the number of seconds since the object's release, and y represents the objects height in feet a. After (blank), this object reached its maximum height of (blank)

b. This object flew for (blank) before it landed on the ground.

c. This object was (blank) in the air 22 s after its release.

d. This object was 3600 ft high at two times: once (blank) after it's release, and again later (blank) after it's release.

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An object was shot up into the air with an initial vertical speed of 544 feet per second. Its height...