A particle of mass 2 units moves along the x-axis and has position function x(t).where t is in seconds. It starts at rest at x(0)= 10. It is subject to a force numerically equal to
-8x(t). (So it is proportional to the distance from the origin and directed toward it). It also experiences a drag (damping) force proportional to its velocity equal to 8x'(t). Where is the particle after 5 seconds?...Hint: mass * acceleration equals total applied force, and the drag force tends to decrease acceleration, so it would be negative. This is for differential equations class, please show work I want to learn this.

use this formula:

p(a\b) = p(a and b)/p(b).

take it from here.

options a,b,c are the right answer.

step-by-step explanation:

a linear parent function is always represented as y = x

if we write this function in the form of y=mx+c

⇒

or  

now if we plot a graph we will find these characteristics:

1) y intercept of the graph is zero so its a straight line passing through origin.

2) as we can see in both the forms of function written, values of x and y may be either positive or negative for the positive slope means points on the graph are either in first quadrant or in third one.

3) it's slope is one.

a 360 degree rotation

step-by-step explanation:

ummm seems that u didnt post the attachement !