In a recent survey of 655 working Americans ages 25-34, the average weekly amount spent on lunch was 43.76 with standard deviation 2.67. The weekly amounts are approximately bell-shaped. (c) Between what two values will approximately 95% of the amounts be?

Between 38.42 and 49.1.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean of 43.76, standard deviation of 2.67.

Between what two values will approximately 95% of the amounts be?

By the Empirical Rule, within 2 standard deviations of the mean. So

43.76 - 2*2.67 = 38.42

43.76 + 2*2.67 = 49.1

Between 38.42 and 49.1.

answer: if you weigh 60 pounds on earth, on the moon you will weigh about 10 pounds. if you weigh 120 pounds on earth, you will weigh about 20 pounds on the moon. since weight is caused by the mass of two objects that are near each other, the bigger the objects, the more the force of gravity.

step-by-step explanation: if you weigh 60 pounds on earth, on the moon you will weigh about 10 pounds. if you weigh 120 pounds on earth, you will weigh about 20 pounds on the moon. since weight is caused by the mass of two objects that are near each other, the bigger the objects, the more the force of gravity.

~dasgupta/mathbook/append17dec2k8.pdf