What is the probability of flipping a coin 12 times and getting heads 3 times? Round your answer to the nearest tenth of a percent. O A. 5.4% O B. 12.5% O C. 12.1% O D. 19.3% SUBMIT​

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Explanation:

We use the binomial probability formula here

P(k) = (n C k)*(p)^k*(1-p)^(n-k)

In this case, there are n = 12 trials and p = 0.5 is the probability of getting heads. The value of k = 3 means we want 3 heads.

So,

P(k) = (n C k)*(p)^k*(1-p)^(n-k)

P(3) = (12 C 3)*(0.5)^3*(1-0.5)^(12-3)

P(3) = 220*(0.5)^3*(1-0.5)^(12-3)

P(3) = 0.0537109375

P(3) = 0.054

P(3) = 5.4%

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Side note: the n C k refers to the nCr combination formula

where the exclamation marks mean factorials. You could also use Pascal's Triangle as an alternative for this portion.

step-by-step explanation:

ok one would be money, and the other would be refreshments or something similar. if each bag of popcorn is 5.00 and each drink is half of that that means drinks are 2.50 the proper way to do that would to look and see how much of each you can buy without exceeding a limit of 30.00