A bag contains 4 blue and 6 green marbles. Two marbles are selected at random from the bag. If the first marble is NOT replaced before the second marble is drawn, what is the probability of getting blue on the 2nd draw, GIVEN YOU DREW GREEN ON THE FIRST DRAW?

Step-by-step explanation:

probability of event # 1 + probability of event # 2 = probability of picking green then blue

probability of event # 1 - chance of drawing green / total # of the possiblities

chance of drawing green = 6

total # of the possibilities = 4(blue) + 6(blue)

total # of the possibilities = 10

probability of event # 1 - 6/10 or 3/5

probability of event # 2 - chance of drawing blue / total # of the possibilities - 1 green

chance of drawing blue = 4

total # of the possibilities - 1 green = 10 - 1

total # of the possibilities - 1 green = 9

probability of event # 2 - 4/9

probability of picking green then blue = 3/5 + 4/9

3 x 4       12

 =

5 x 9       45

probability of picking green then blue = 12/45 or 4/15

let's cover over the formula of the vertex:

y = a(x – h)^2 + k

in this formula, (h,k) are the vertex, always remember that the positive or negative value of the vertex is based on the sign it has.

for example, if the vertex is -3,-6 then both the x and y value would have the positive sign attached to it and if it were a positive x and y value, then a negative sign would be attached to it.

with that being said, for our problem the x value is a positive one so we are looking for a number with a negative sign next to it, in this case the first and second choice.

however, for the first answer choice it isn't quite part of the formula so we know that the answer choice correctly displays the x value.

to confirm, we can see if the -1 fits correctly with the second answer choice, and as mentioned above a negative number will have a positive sign attached to it. so, for our problem we can see that -1 has been changed to +1, so we can confirm that the second answer choice is correct.

hence, our final answer is y=(x - 1)^2 + 1

definitely a. the others have almost all data points on one side of the line.

step-by-step explanation: